Chapter 31: Atomic Physics Selected Solutions

Selected Solutions

7. For the Lyman series we have:

The last form of the equation makes clear that the longest wavelength corresponds to the smallest n. Since, R = 1.097 x 10⁷m^-1, we have

19. (a) The photon's energy must equal the energy difference between the two states. Since the energy of a photon is given by , we can use the expression for the wavelengths to get

.

(b) The energy of the photon would be less than that found in part (a), because the absolute values of the lower n energy state differences are greater than those of the higher n energy state differences, and in both cases Dn = 2.

(c)

59. (a) Using the expression for the radius of the orbit, we get

© 2000-2002 by Prentice-Hall, Inc. A Pearson Company Distance Learning at Prentice Hall Legal Notice