Chapter 22: Magnetism Selected Solutions

Selected Solutions

17. By conservation of energy, the magnitude of the electric potential energy lost by the electron, eV, is converted into kinetic energy. Therefore,

We can rewrite the expression for the radius of the path to solve for B

19. (a) According to the right-hand rule, a positive charge would exprience a force to the left. Since the particle is experiencing a force to the right, it must have negative charge.

(b) We can rewrite the expression for the radius of the path to solve for m

35. Since t = IABsinq, and we are given that , therefore, . Thus,

.

47. (a) The force per unit length is given by

(b) Assuming that the lengths of each wire are the same, the force per meter exerted on the 4.33-A wire is the same as the force per meter exerted on the 1.75-A wire because these forces form an action-reaction pair.

61. The magnetic field at each point is the vector sum of the magnetic fields due to each wire

Selected Solutions by David Reid, Eastern Michigan University. ©2002 by Prentice Hall, Inc.

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